0=x^2-9x-162

Solution for 0=x^2-9x-162 equation:

0=x^2-9x-162

We move all terms to the left:

0-(x^2-9x-162)=0

We add all the numbers together, and all the variables

-(x^2-9x-162)=0

We get rid of parentheses

-x^2+9x+162=0

We add all the numbers together, and all the variables

-1x^2+9x+162=0

a = -1; b = 9; c = +162;
Δ = b2-4ac
Δ = 92-4·(-1)·162
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-27}{2*-1}=\frac{-36}{-2}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+27}{2*-1}=\frac{18}{-2}
=-9
$